Tutorial for equivalent length calculation
This tutorial uses sample calculations to demonstrate how to calculate equivalent length for piping fittings, joints and valves.
Problem Statement -
Calculate the equivalent length and combinedK-factorfor following set of fittings,900elbows - 5 nos. 450elbows - 2 nos.Gate valves - 3 nos.Ball valve - 1 no.Check valve - 1 no. The line size is 6 inches while there is a 8"-6"reducerat the beginning of the line.
The 6" line with 'STD' schedule handles 100,000 kg/hr of water. Approximate length of this line is around 200m. This water stream is available at 5 barg pressure and 300C.
Solution -
This sample problem is solved in following 3 basic steps.
Step 1.
第一步解决这个示例的problem requires determination the important physical properties of given fluid (water) at given temperature and pressure conditions.
UsingEnggCyclopedia's Liquid Density Calculator, water density at 300C =993.41 kg/m3
UsingEnggCyclopedia's Liquid Viscosity Calculator, water viscosity at 300C =0.81 cP
FromEnggCyclopedia's standard pipe dimensions calculator, for 6" pipe with STD schedule, internal diameter is 154.1 mm.
Step 2.
Total K factor for the set of fittings can be calculated usingEnggCyclopedia's K factor calculator.Refer to the screenshot below for demonstration of use of this calculator.
Step 3.
In the third step of solving this sample problem, inputs from steps 1 and 2 are fed toEnggCylopedia's equivalent length calculatorto get equivalent length for the given set of fittings. Refer to the screenshot given below for guidance to use the calculator.






